-x^2-4x-12=-8

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Solution for -x^2-4x-12=-8 equation: 



-x^2-4x-12=-8

We move all terms to the left:

-x^2-4x-12-(-8)=0

We add all the numbers together, and all the variables

-1x^2-4x-4=0

a = -1; b = -4; c = -4;
Δ = b2-4ac
Δ = -42-4·(-1)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{4}{-2}=-2$

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